Be-A-Computer: Weeks 5-8¶
The purpose of these problems is to allow you to test your understanding of Classes and Recursion. Each section should not take more than an hour to complete.
You should do these warm-up exercises by hand. We provide files that will allow you to check your answers.
To get started run git pull upstream master
, which will pick up a
directory named bac5-8
.
Classes and Objects¶
You can check your answers by running the Python program classes.py
in bac5-8
Warm-up exercise: This warm-up exercise uses the following constants and data:
(DATE, TICKER, OPEN, CLOSE) = (0, 1, 2, 3)
stocks = [['Date', 'Ticker Symbol', 'Open', 'Close'],
['2010-11-09', 'AMD', '8.22', '7.91'],
['2010-11-09', 'GOOG', '630.00', '624.82'],
['2010-11-09', 'QQQ', '53.95', '54.26'],
['2010-11-10', 'AMD', '8.22', '8.72'],
['2010-11-10', 'BSB', '620.00', '630.40'],
['2010-11-10', 'GOOG', '630.00', '630.40'],
['2010-11-10', 'QQQ', '53.95', '53.45'],
['2010-11-11', 'AMD', '8.22', '8.40'],
['2010-11-11', 'GOOG', '630.00', '634.82'],
['2010-11-11', 'QQQ', '53.95', '53.45']]
What is the output of the following code?
class Stock_Info(object):
def __init__(self, date, ticker, opening_price, closing_price):
self._date = date
self._ticker = ticker
self._opening_price = opening_price
self._closing_price = closing_price
@property
def date(self):
return self._date
@property
def ticker(self):
return self._ticker
@property
def opening_price(self):
return self._opening_price
@property
def closing_price(self):
return self._closing_price
@closing_price.setter
def closing_price(self, correct_value):
self._closing_price = correct_value
def __repr__(self):
return "|".join([self.date, self.ticker,
self.opening_price, self.closing_price])
def create_dict(data):
rv = {}
for row in data:
tkr = row[TICKER]
s = Stock_Info(row[DATE], tkr, row[OPEN], row[CLOSE])
if tkr not in rv:
rv[tkr] = []
rv[tkr].append(s)
return rv
def mystery(d, list0):
for (x, y, z) in list0:
for a in d[x]:
if a.date == y:
a.closing_price = z
break
d = create_dict(stocks)
entries = [["GOOG", '2010-11-09', '625.00'],
['GOOG', '2010-11-10', '634.82']]
mystery(d, entries)
for s in d["GOOG"]:
print(s)
Recursion¶
You can check your answers by running the Python program recursion.py
in bac5-8
Warm-up exercise #1: What is the output of the following code?
def mystery(a, b, c, d):
if c == 0:
return d
elif c % 2 == 0:
return b + mystery(a, b, c - 2, d)
else:
return a + mystery(a, b, c - 1, d)
print("Warmup Exercise #1")
print(mystery("x", "y", 6, "z"))
print(mystery("x", "y", 5, "z"))
print()
Warm-up exercise #2: What is the output of the following code?
def flip(s, a):
if a == 0:
return s
for i in range(a):
if s[i] == "*":
s[i] = "-"
else:
s[i] = "*"
return flip(s, a//2)
print("Warmup Exercise #2")
s = []
for i in range(64):
s.append("*")
s = flip(s, 64)
t = ""
for c in s:
t = t + c
print(t)